Home
Class 12
MATHS
The numbers of natural numbers lt 300 th...

The numbers of natural numbers `lt 300` that are divisible by 6 but not by 9 :

A

49

B

37

C

33

D

16

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of natural numbers less than 300 that are divisible by 6 but not by 9, we can follow these steps: ### Step 1: Find the count of natural numbers less than 300 that are divisible by 6. To find the count of numbers divisible by 6, we can use the formula for the nth term of an arithmetic progression (AP): \[ n = \frac{\text{Last term} - \text{First term}}{\text{Common difference}} + 1 \] Here, the first term \(A\) is 6, the common difference \(d\) is 6, and the last term is the largest multiple of 6 less than 300, which is 294. So, we set up the equation: \[ n = \frac{294 - 6}{6} + 1 \] Calculating this gives: \[ n = \frac{288}{6} + 1 = 48 + 1 = 49 \] Thus, there are **49 natural numbers less than 300 that are divisible by 6**. ### Step 2: Find the count of natural numbers less than 300 that are divisible by both 6 and 9 (i.e., divisible by 18). Next, we find the count of numbers divisible by 18. Again, we use the formula for the nth term of an AP: Here, the first term \(A\) is 18, the common difference \(d\) is 18, and the last term is the largest multiple of 18 less than 300, which is 288. So, we set up the equation: \[ n = \frac{288 - 18}{18} + 1 \] Calculating this gives: \[ n = \frac{270}{18} + 1 = 15 + 1 = 16 \] Thus, there are **16 natural numbers less than 300 that are divisible by 18**. ### Step 3: Subtract the count of numbers divisible by 18 from the count of numbers divisible by 6. Now, we subtract the count of numbers divisible by 18 from the count of numbers divisible by 6 to find those that are divisible by 6 but not by 9: \[ \text{Count of numbers divisible by 6 but not by 9} = 49 - 16 = 33 \] Thus, the final answer is that there are **33 natural numbers less than 300 that are divisible by 6 but not by 9**. ### Summary of Steps: 1. Count numbers divisible by 6: 49 2. Count numbers divisible by 18: 16 3. Subtract to find numbers divisible by 6 but not by 9: 33
Promotional Banner

Topper's Solved these Questions

  • SEQUENCE AND SERIES

    VIKAS GUPTA (BLACK BOOK)|Exercise EXERCISE (ONE OR MORE THAN ONE ANSWER IS/ARE CORRECT)|18 Videos
  • SEQUENCE AND SERIES

    VIKAS GUPTA (BLACK BOOK)|Exercise EXERCISE (COMPREHENSION TYPE PROBLEMS)|17 Videos
  • QUADRATIC EQUATIONS

    VIKAS GUPTA (BLACK BOOK)|Exercise EXERCISE (SUBJECTIVE TYPE PROBLEMS)|45 Videos
  • SOLUTION OF TRIANGLES

    VIKAS GUPTA (BLACK BOOK)|Exercise Exercise-5 : Subjective Type Problems|12 Videos

Similar Questions

Explore conceptually related problems

How many natural number upto 990 are divisible by 5 & 9 both but not by 7?

The number of numbers that are divisible by 9 between 1and 1000

The sum of all natural numbers less than 400 which are NOT divisible by 6, is

Find the sum of all natural numbers n in [100, 300] that are neither divisible by 4 nor by 6.

Find the number of natural numbers divisible by 5 between 1 and 1000.

Property 1 If a number is divisible by another number then it is divisible by each of the factors of that number.If abc are three natural numbers such that a is divisible by b and b is divisible by c then a is divisible by c also.

VIKAS GUPTA (BLACK BOOK)-SEQUENCE AND SERIES -EXERCISE (SUBJECTIVE TYPE PROBLEMS)
  1. The numbers of natural numbers lt 300 that are divisible by 6 but not ...

    Text Solution

    |

  2. Let a ,b ,c ,d be four distinct real numbers in A.P. Then half of the ...

    Text Solution

    |

  3. The sum of all digits of n for which sum (r =1) ^(n ) r 2 ^(r ) = 2+2^...

    Text Solution

    |

  4. If lim ( x to oo) (r +2)/(2 ^(r+1) r (r+1))=1/k, then k =

    Text Solution

    |

  5. The value of sum (r =1) ^(oo) (8r)/(4r ^(4) +1) is equal to :

    Text Solution

    |

  6. Three non-zero real numbers from an A.P. and the squares of these numb...

    Text Solution

    |

  7. The sum of the fourth and twelfth term of an arithmetic progression is...

    Text Solution

    |

  8. In an increasing sequence of four positive integers, the first 3 terms...

    Text Solution

    |

  9. The limit of (1)/(n ^(4)) sum (k =1) ^(n) k (k +2) (k +4) as n to oo i...

    Text Solution

    |

  10. Which is the last digit of 1+2+3+……+ n if the last digit of 1 ^(3) + ...

    Text Solution

    |

  11. There distinct positive numbers, a,b,c are in G.P. while log (c) a, lo...

    Text Solution

    |

  12. The numbers 1/3, 1/3 log (x) y, 1/3 log (y) z, 1/7 log (x) x are in H...

    Text Solution

    |

  13. If sum ( k =1) ^(oo) (k^(2))/(3 ^(k))=p/q, where p and q are relativel...

    Text Solution

    |

  14. The sum of the terms of an infinitely decreassing Geometric Progressio...

    Text Solution

    |

  15. A cricketer has to score 4500 runs. Let a (n) denotes the number of ru...

    Text Solution

    |

  16. If x=10 sum(r=3) ^(100) (1)/((r ^(2) -4)), then [x]= (where [.] deno...

    Text Solution

    |

  17. Let f (n)=(4n + sqrt(4n ^(2) +1))/( sqrt(2n +1 )+sqrt(2n-1)),n in N th...

    Text Solution

    |

  18. Find the sum of series 1+1/2+1/3+1/4+1/6+1/8+1/9+1/12+…… oo, where the...

    Text Solution

    |

  19. Let a (1), a(2), a(3),…….., a(n) be real numbers in arithmatic progres...

    Text Solution

    |

  20. Let the roots of the equation 24 x ^(3) -14x ^(2) + kx +3=0 form a geo...

    Text Solution

    |

  21. How many ordered pair (s) satisfy log (x ^(2) + (1)/(3) y ^(3) + (1)/(...

    Text Solution

    |