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A consignment of 15 record players conta...

A consignment of 15 record players contain 4 defectives. The record players are selected at random, one by one and examined. The one examined is not put back. Then :

A

Probability of getting exactly 3 defectives in the examination of 8 record players is `(""^(4)C_(3)""^(11)C_(5))/(""^(15)C_(8))`.

B

Probability that `9^(th)` one examined is the last defective is `(8)/(197)`.

C

Probability that `9^(th)` examined record player is defective, given that there are 3 defectives in first 8 players examined is `(1)/(7)`.

D

Probability that `9^(th)` one examined is the last defective is `(8)/(195)`.

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The correct Answer is:
A, C, D
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