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the lines x + y + 1 = 0; 4x + 3y + 4 = ...

the lines `x + y + 1 = 0; 4x + 3y + 4 = 0` and `x + alphay + beta= 0,` where `alpha^2 + beta^2 = 2,` are concurrent

A

` alpha = 1 , beta = -1 `

B

` alpha = 1 , beta = pm 1 `

C

` alpha = -1 , beta = pm 1 `

D

` alpha = pm 1 , beta = 1 `

Text Solution

Verified by Experts

The correct Answer is:
D
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