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From a point P=(3, 4) perpendiculars PQ ...

From a point` P=(3, 4)` perpendiculars `PQ` and `PR` are drawn to line `3x +4y -7=0` and a variable line `y -1= m (x-7)` respectively then maximum area of triangle `PQR` is :

A

10

B

12

C

6

D

9

Text Solution

Verified by Experts

The correct Answer is:
D
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