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A straight line L intersects perpendicul...

A straight line L intersects perpendicularly both the lines :
`(x+2)/(2)=(y+6)/(3)=(z-34)/(-10) and (x+6)/(4)=(y-7)/(-3)=(z-7)/(-2)`,
then the square of perpendicular distance of origin from L is

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Prove that the lines (x+1)/(3)=(y+3)/(5)=(z+5)/(7) and (x-2)/(1)=(y-4)/(4)=(z-6)/(7) lines.

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Knowledge Check

  • The lines (x)/(1)=(y)/(2)=(z)/(3)and(x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

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    2
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    3
  • The lines (x-1)/2= (y-2)/4 = (z-3)/6 and (x-1)/4 = (y-2)/5 = (z-3)/7 are

    A
    perpendicular
    B
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    C
    intersecting
    D
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