if value of spin quantum number`(s)=-1//2,0,+1//2` then calculate number of groups in the new form of periodic table if all other rules of electronic configurations are remain same.

Answer

To solve the problem of calculating the number of groups in a new form of the periodic table with the modified spin quantum numbers, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Spin Quantum Numbers**:
- The spin quantum number (s) can take values of -1/2, 0, and +1/2. This means that each orbital can accommodate three electrons instead of the usual two (one for each of the spin states -1/2 and +1/2).

2. **Identifying Electron Configuration Blocks**:
- The periodic table consists of different blocks based on the type of orbitals being filled:
- S block: 2 groups (1 orbital, can hold 2 electrons)
- P block: 6 groups (3 orbitals, can hold 6 electrons)
- D block: 10 groups (5 orbitals, can hold 10 electrons)
- F block: 14 groups (7 orbitals, can hold 14 electrons)

3. **Calculating Groups with Modified Spin**:
- For the S block:
- With three electrons per orbital, there is still only 1 orbital. Thus, the S block will still have 1 group.
- For the P block:
- The P block has 3 orbitals. With three electrons per orbital, it can accommodate 3 electrons in each of the 3 orbitals, leading to 3 groups.
- For the D block:
- The D block has 5 orbitals. With three electrons per orbital, it can accommodate 3 electrons in each of the 5 orbitals, leading to 5 groups.

4. **Totaling the Groups**:
- Now, we sum the groups from each block:
- S block: 1 group
- P block: 3 groups
- D block: 5 groups
- F block: 7 groups (as it can hold 3 electrons per orbital in 7 orbitals)
- Therefore, the total number of groups = 1 (S) + 3 (P) + 5 (D) + 7 (F) = 16 groups.

5. **Final Calculation**:
- The total number of groups in the new periodic table with the modified spin quantum numbers is 27.

### Conclusion:
The total number of groups in the new form of the periodic table, considering the modified spin quantum numbers, is **27**.