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The melting point of RbBr is 682^(@)C, w...

The melting point of `RbBr` is `682^(@)C`, while that of `NaF` is `988^(@)C` . The principla reason that melting point of `NaF` is much higher than that of `RbBr` is that `:`

A

The molar mass of NaF is smaller than that of RbBr

B

the bond of RbBr has more covalent character than the bond in NaF

C

the difference in electronegativity between Rb and Br is maller the difference between Na and F

D

the intermoleculear distance, `r_(c)+r_(a)` is greater for RbBr than for NaF

Text Solution

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The correct Answer is:
D
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