Select the correct statement(s) about the compound `NO[BF_(4)]:`

Options

A. It has `5sigma and 2pi` bond
B. Nitrogen-oxygen bond length is higher than nitric oxide `(NO)`
C. It is a diamagnetic species
D. `B-F` bond length in this compound is lower than in `BF_(3)`

Answer

A, C

Explanation

`NO^(+)[BF_(4)]^(-)`
No. of `sigma` bonds in `[BF_(4)]^(-)=4`
`implies` B.O of `NO^(+)=3.0` i.e., one sigma bond and two pi bonds
`therefore` No. of `pi` bonds =2
No. of `sigma` bonds =5
`implies` B.O of `NO^(+)=3.0`
and B.O of NO=2.5
`implies NO^(+)` is diamagnetic and `BF_(4)^(-)` is also diamagnetic
`impliesB-F` bonds are longer in `BF_(4)^(-)` than in `BF_(3)` due to absence of `ppi-ppi` back bonding in `[BF_(4)]`