The hybridization of central atoms of compounds A, B, C and D are `sp^(3)d, sp^(3), sp^(2) and sp` respectively. If compounds A and D have same shape like `I_(3)^(-)` and compounds B and C have same shape like water structure. Then calculate value of "P+Q+R+S", where P, Q, R, and S are number of lone pairs on central atoms of compounds A, B, C and D respectively.

Answer

`6`

Explanation

P=3 Q=3 R=1 S=0
Hence P+Q+R+S=6