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If acos2theta+bsin2theta=c" has "theta(...

If `acos2theta+bsin2theta=c" has "theta_(1),theta_(2)` as its solutions then show that `tantheta_(1)+tantheta_(2)=(2b)/(c+a)tantheta_(1).tantheta_(2)=(c-a)/(c+a)` and hence show that `tan(theta_(1)+theta_(2))=b//a`.

Text Solution

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The correct Answer is:
`(b)/(a)`
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