Solve the equation `1 + sin^(2) theta = 3 sin theta cos theta`.

The maximum value of the expression (1)/( sin^(2) theta + 3 sin theta cos theta + 5cos^(2) theta) is

Solve the following equations 2Sin^(2) theta = Sin theta, theta in (0, pi)

If 1+sin^(2)theta = 3 sin theta cos theta , then theta =

Solutions of the equation sin (sqrt(1 + sin 2 theta)) = sin theta + cos theta " is " (n in Z)

If 0 lt theta lt pi/2 , the solution of the equation sin theta - 3 sin 2 theta + sin 3 theta = cos theta - 3 cos 2 theta + cos 3 theta is

Solution of the equation sin(sqrt(1+sin 2 theta))=sin theta+cos theta is ( n in Z)