Find the distance of a point (2,5,-3) from the planer r.(6i-3j+2k)=4

Find the distance of a point (2,5,-3) form plane bar(r ).(6bar(i) - 3bar(j) + 2bar(k)) = 4 .

Let P,Q,R be points with poistion vectors r_(1) = 3i - 2j - k, r_(2) = I + 3j + 4k and r_(3) = 2i + j - 2k relavtive to an origin. The distance of P from the plane OQR is

Find the angle between the planes vec(r).(2vec(i)-vec(j)+2vec(k))=3 an vec(r).(3vec(i)+6vec(j)+vec(k))=4 .

A particle acted on by constant forces 4i + j - 3k and 3i + j - k is displaced from the point I + 2j + 3k to the point 5i + 4j + k. The total work done by the forces is

Find the equation of the line passing through the point 2bar(i)+3bar(j)-4bar(k) and parallel to the vector 6bar(i)+3bar(j)-2bar(k) in cartesian form.