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SRISIRI PUBLICATION-QUESTION PAPER -Section B
- Solve 1+sin^2 theta=3sin thetacostheta
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- Solve tan theta + 3 cot theta = 5 "sec" theta.
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- If acos2theta+bsin2theta=c" has "theta(1),theta(2) as its solutions ...
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- Given pnepmq . Show that the solutions of cosPtheta+cosqtheta=0 for...
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- Prove that Sin^-1""3/5+Sin^-1""8/17=Cos^-1""36/85
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- P.T. Cos^(-1)((4)/(5))+Sin^(-1)((3)/(sqrt34))=Tan^(-1)((27)/(11)).
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- Find the value of tan(Sin^(-1)3/5 + Cos^(-1) 5/(sqrt34)).
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- Show that cos(2Tan^(-1).(1)/(7))=sin(2Tan^(-1).(3)/(4))
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- Prove that tan^(-1)((1)/(2))+tan^(-1)((1)/(5))+tan^(-1)((1)/(8))=(pi)/...
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- Prove that sin^(-1)((4)/(5))+2 Tan^(-1)((1)/(3)) = (pi)/2.
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- If Cos^(-1)p+Cos^(-1)q+Cos^(-1)r = pi then, P.T. p^(2)+q^(2)+r^(2) = 2...
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- Prove that sin[Cot^(-1) (2x)/(1-x^2)+Cos^(-1)((1-x^(2))/(1+x^(2)))]=1.
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- Prove that cot A + cot B + cot C = (a^(2)+b^(2)+c^(2))/(4/\).
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- Show that a^(2)cotA+b^(2)cotB+c^(2)cotC=(abc)/(R)
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- If C=60^(@), " then show that"(a)/(b+c)+(b)/(c+a)=1
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- If cot A/2:cot"" B/2: cot"" C/2 = 3:5:7 then show that a:b:c = 6:5:4.
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- In a /\ABC, if a:b:c = 7:8:9, then find cosA:cosB:cosC.
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- Value of 1/(r(1)^2)+ 1/(r(2)^2)+ 1/(r(3)^2)+ 1/(r()^2) is :
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- Show that r(1)+r(2)+r(3)-r=4R
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- Show that r+r(3)+r(1)-r(2)=4RcosB.
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