`int(dx)/(9x^2+6x+10)`

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Evaluate int(dx)/(x^2+6x+10)

Find the following integrals : (i) int(dx)/(x^(2)-6x+13)int(dx)/(3x^(2)+13x-10)int(dx)/(sqrt(5x^(2)-2x))

Evaluate : (i) int(dx)/((9x^(2)-1)) (ii) int(x)/((x^(4)-9))dx (iii) int(x^(2))/((x^(2)-9))dx

The value of int(dx)/((x^(2)-6x+9)sqrt(x^(2)-6x+4)) is

int(1)/(x^(2)+6x+10)dx=

int (1)/(x^(2)+6x+10))dx=

(i) int_1^3 (3x)/(9x^2-1) dx (ii) int_2^3 x/(x^2+1) dx