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let (i) (pvvq)^^(pvv~q), (ii) (p^^q)^^(...

let (i) `(pvvq)^^(pvv~q), (ii) (p^^q)^^(qvv~q), (iii). (pvvq)^^(pvv~q), (iv) (pvvq)vv(p^^~q)` then which one is tautology

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let (i) (p vv q)^^(p vv sim q),(ii)(p^^q)^^(q vv sim q),(iii).(p vv q)^^(p vv sim q),(iv)(p vv q)vv(p^^sim q) then which one is tautology

(p^^~q) ^^ (~pvvq) is

(p^^~q) ^^ (~pvvq) is

(p^^~q) ^^ (~pvvq) is

((pvvq)^^~p) to q

Prove that [(p^^~q)vv(q^^~p)]^^(pvvq)=(pvvq)^^(~qvv~p)^^(pvvq)

(~(pvvq))vv(~p^^q) is logically equivalent to

(~(pvvq))vv(~p^^q) is logically equivalent to

(~(pvvq))vv(~p^^q) is logically equivalent to