The lattice enthalpy of solid `NaCI` is `772 kJ mol^(-1)` and enthalpy of solution is `2kJ mol^(-1)`. If the hydration enthalpy of `Na^(+) &CI^(-)` ions are in the ratio of 3: 25, what is the magnitude of enthalpy of hydration (in kJ) of chloride ion ?

The lattice enthalpy of solid NaCl is 772 kJ mol^(-1) and enthalpy of solution is 2 kJmol^(-1) . If the hydration enthaply of Na^(+) & Cl^(-) ions are in the ratio of 3 : 2.5 , what is the enthalpy of hydration of chloride ion ?

Lattice energy of NaCl(s) is -790 kJ " mol"^(-1) and enthalpy of hydration is -785 kJ " mol"^(-1) . Calculate enthalpy of solution of NaCl(s).

Lattice energy of NaCl(s) is -790 kJ " mol"^(-1) and enthalpy of hydration is -785 kJ " mol"^(-1) . Calculate enthalpy of solution of NaCl(s).

Lattice energy of NaCl_((s)) is -788kJ mol^(-1) and enthalpy of hydration is -784kJ mol^(-1) . Calculate the heat of solution of NaCl_((s)) .

Lattice energy of NaCl_((s)) is -788kJ mol^(-1) and enthalpy of hydration is -784kJ mol^(-1) . Calculate the heat of solution of NaCl_((s)) .

The lattice energy of solid NaCI is 180 kcal mol^(-1) . The dissolution of the solid in H_(2)O is endothermic to the extent of 1.0 kcal mol^(-1) . If the hydration energies of Na^(o+) and CI^(Theta) ions are in the ratio of 6:5 what is the enthalpy of hydration of sodium ion?

The lattice energy of solid NaCI is 180 kcal mol^(-1) . The dissolution of the solid in H_(2)O is endothermic to the extent of 1.0 kcal mol^(-1) . If the hydration energies of Na^(o+) and CI^(Theta) ions are in the ratio of 6:5 what is the enthalpy of hydration of sodium ion?

The enthalpy of solution of sodium chloride is 4 kJ mol^(-1) and its enthalpy of hydration of ion is -784 kJ mol^(-1) . Then the lattice enthalpy of NaCl (in kJ mol^(-1) ) is

The enthalpy of solution of sodium chloride is 4 kJ mol^(-1) and its enthalpy of hydration of ion is -784 kJ mol^(-1) . Then the lattice enthalpy of NaCl (in kJ mol^(-1) ) is