The equation of tangent to the curve `y=x^(2)+4x+1` at (-1,-2) is

The equation of tangent to the curve y= x^2 +4x+ 1 at (-1, 1) is...... A) 2x-y+3=0 B) 2x+y-5=0 C) 2x-y-1 =0 D) x+y-1 =0

The equation of tangent to the curve y=4 xe^(x) at (-1,(-4)/(e )) is

The equation of the tangent to the curve y=x^3+1 at (1,2) is

The equation of the tangent to the curve y=4xe^(x) at (-1,(-4)/e) is

The equation of the tangent to the curve y = e^(2x) at (0,1) is

Find the equation of the tangent to the curve y=3x^2 at (1,1)

Find the equation of the tangent to the curve y=3x^2 at (1,1)

Find the equation of the tangent of the curve y=3x^(2) at (1, 1).

(i) Find the equation of tangent to curve y=3x^(2) +4x +5 at (0,5) (ii) Find the equation of tangent and normal to the curve x^(2) +3xy+y^(2) =5 at point (1,1) on it (iii) Find the equation of tangent and normal to the curve x=(2at^(2))/(1+t^(2)) ,y=(2at^(2))/(1+t^(2)) at the point for which t =(1)/(2) (iv) Find the equation of tangent to the curve ={underset(0" "x=0)(x^(2) sin 1//x)" "underset(x=0)(xne0)" at "(0,0)