[" A small block of mass of "0.1kg" lies on a fixed inclined plane 'PQ' which makes an angle 'Owalins "],[" Nats on the block through its centre of mass as shown in the figure The block remains stat "],[(e)/(1)=]

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle theta with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in the figure. The block remains stationary if ( take g=10 m//s^(2))

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle theta with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in figure. The block remains stationary if (take g=10m//s^2 )

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle theta with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in the figure. The block remains stationary if ( take g=10 m//s^(2))

A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle theta with the horizontal. A horizontal force of 1N acts on the block through its centre of mass as shown in figure. The block remains stationary if (take g=10m//s^2 )

The acceleration of the 10 kg mass block shown in the figure is : -

The acceleration of the 10 kg mass block shown in the figure is : -

A horizontal force F is applied to a block of mass m on a smooth fixed inclined plane of inclination theta to the horizontal as shown in the figure. Resultant force on the block up the plane is:

A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is