Area enclosed by `f(x) = ln (x - 2)-1/x,x = 6, x = 10` and x-axis is :

Find area bounded by y = f^(-1)(x), x = 4, x = 10 and the x -axis, given that the area bounded by y = f(x) , x = 2, x = 6 and the x -axis is 30 sq. units, where f(2) = 4 and f(6) = 10 , and that f(x) is an invertible function.

The area enclosed by y=ln x, its normal at (1,0) and the y -axis is

The area enclosed by y = x(x - 1)(x - 2) and x-axis, is given by

The area enclosed by y = x(x - 1)(x - 2) and x-axis, is given by

The area the region enclosed by f(x)=x^(3)-10x and g(x)=6x, x ge 0, y ge 0 is

The area enclosed by the parabola ay = 3 (a^(2) - x^(2)) and x-axis is

The area enclosed by the parabola ay = 3 (a^(2) - x^(2)) and x-axis is

Find the area enclosed by y=g(x), x-axis, x=1 and x=37, where g(x) is inverse of f(x)=x^(3)+3x+1 .

Find the area enclosed by y=g(x), x-axis, x=1 and x=37, where g(x) is inverse of f(x)=x^(3)+3x+1 .