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If (b2-b1)(b3-b-1)+(a2-a1)(a3-a1)=0, the...

If `(b_2-b_1)(b_3-b-1)+(a_2-a_1)(a_3-a_1)=0`, then prove that the circumcenter of the triangle having vertices `(a_1,b_1),(a_2,b_2)` and `(a_3,b_3)` is `((a_2+a_3)/(2),(b_2+b_3)/(2))`.

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