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" 1."quad " 케였다 A "=[[2,5,19,-7],[35,-2,...

" 1."quad " 케였다 A "=[[2,5,19,-7],[35,-2,(5)/(2),12],[sqrt(3),1,-5,17]]," For कोजिए: "

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Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= b_(ij) = [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: a_23 …

Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= [b_(ij) ]= [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: a_31 =…

Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= b_(ij) = [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: order of the matrix A is..

Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= b_(ij) = [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: order of matrix B is.

Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= [b_(ij) ]= [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: a_31 =…

Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= b_(ij) = [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: a_23 …

Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= b_(ij) = [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: order of the matrix A is..

Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= b_(ij) = [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: order of matrix B is.

In the matrix A = [[2,5,19,-7],[35,-2,5/2,12],[sqrt3,1,-5,17]] , write: The order of the matrix.

Let A=[a_(ij)] = [[1,-2,5],[3,4,-6],[9,15,13]] and B= b_(ij) = [[ 2,5,19,-7],[35,-2,5/2,12],[sqrt(3),1,-5,17]] Then: the number of elements in A andB is……