Let `cos(alpha+beta)=(4)/(5)` and let `sin(alpha-beta)=(5)/(13)`, where `0 le alpha`, `beta=(pi)/(4)`. Then`tan2alpha=`

Let cos(alpha+beta)=(4)/(5) and let sin(alpha-beta)=(5)/(13), where 0<=alpha,beta<=(pi)/(4) Then tan2 alpha=(36)/(33) b.(19)/(12) c.(20)/(7)d*(25)/(16)

Let cos(alpha+beta)=(4)/(5) and let sin (alpha-beta)=(5)/(13) where 0<=alpha,beta<=(pi)/(4). Then tan2 alpha=(56)/(33)(b)(19)/(12)(c)(20)/(7) (d) (25)/(16)

Let cos(alpha+beta)=(4)/(5) and sin(alpha-beta)=(5)/(13) where 0<=alpha,beta<=(pi)/(4) then find tan(2 alpha)

Let cos(alpha+beta) =4/5 and let sin (alpha-beta)=5/13 where 0 le alpha, beta le (pi)/(4) then tan 2 alpha

Let cos(alpha+beta)=4//5and let sin(alpha-beta)=5//13 , where 0lealpha,betalepi//4 . Then tan2alpha is equal to