The workdone in increasing the length of a one metre long wire of cross `-` sectional area `1 m m^(2)` through `1mm` will be `(Y=2xx10^(11)Nm^(-2)) :`

The work done in increasing the length of a one metre long wire of cross-sectional area 1 mm^(2) through 1 mm will be (Y = 2 xx 10^(11) Nm^(-2))

Calculate the force required to increase the length of a steel wire of cross- sectional area 10^(-6)m^(2) by 0.5% given: Y_(("for steel"))=2xx10^(11)N-m^(2)

A 1 m long steel wire of cross-sectional area 1 mm^(2) is extended 1 mm. If Y = 2 xx 10^(11) Nm^(-2) , then the work done is

The work per unit volume to stretch the length by 1% of a wire with cross sectional area of 1mm^2 will be. [Y=9xx10^(11)(N)/(m^2) ]

The work per unit volume to stretch the length by 1% of a wire with cross sectional area of 1mm^2 will be. [Y=9xx10^(11)(N)/(m^2) ]

A wire of length 50 cm and cross sectional area of 1 sq. mm is extended by 1mm . The required work will be (Y=2xx10^(10) Nm^(-2))

A wire of length 50 cm and cross sectional area of 1 sq. mm is extended by 1mm . The required work will be (Y=2xx10^(10) Nm^(-2))

Work done in stretching a wire of length 1 m and of cross-sectional area 1 mm^(2) through 2 mm if Young's modulus of the material of the wire is 2 xx 10 ^(11) N//m^(2) is .......