A heat source at T = `10^(3)` K is connected to another heat reservoir at T = `10^(2)` K by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is 0.1 `WK^(-1)m^(-1)`, the energy flux through it in steady state is :

A hollow spherical conducting sheel of inner radius R_(1) = 0.25 m and outer radius R_(2) = 0.50 m is placed inside a heat reservoir of temperature T_(0) = 1000^(@)C . The shell is initially filled with water at 0^(@)C . The thermal conductivity of the material is k =(10^(2))/(4pi) W//m-K and its heat capacity is negligible. The time required to raise the temperature of water to 100^(@)C is 1100 ln.(10)/(9) sec . Find K . Take specific heat of water s = 4.2 kJ//kg.^(@)C , density of water d_(w) = 1000 kg//m^(3) pi = (22)/(7)

Steam at 373 K is passed through a tube of radius 10 cm and length 2 m. The thickness of the tube is 5 mm and thermal conductivity of the material is 390 W m^(-1) K^(-1). The outside temperature is 0C. The heat lost per second in J is

One face of a copper plateof area 5m^(2) and thickness 0.01m is in contact with water boiling at 100^(@)C , the other face is at 0^(@)C . Find the heat conducted in one second (K of copper = 400 Wm^(-)K^(-1) )

A rod of 1m length and area of cross-section 1cm^(2) is connected across two heat reservoirs at temperature 100^(@)C and 0^(@)C as shown. The heat flow per second through the rod in steady state will be [Thermal conductivity of material of rod =0.09kilocalm^(-1)s^(-1)('^(@)C) ]

Steam at 373 K is passed through a tube of radius 10 cm and length 10 cm and length 2m . The thickness of the tube is 5mm and thermal conductivity of the material is 390 W m^(-1) K^(-1) , calculate the heat lost per second. The outside temperature is 0^(@)C .

Steam at 373 K is passed through a tube of radius 10 cm and length 10 cm and length 2m . The thickness of the tube is 5mm and thermal conductivity of the material is 390 W m^(-1) K^(-1) , calculate the heat lost per second. The outside temperature is 0^(@)C .

Steam at 373 K is passed through a tube of radius 10 cm and length 10 cm and length 2m . The thickness of the tube is 5mm and thermal conductivity of the material is 390 W m^(-1) K^(-1) , calculate the heat lost per second. The outside temperature is 0^(@)C .

A heater of resistance 20 Omega is used to heat a room at 10^@C and is connected to 220 V mains. The temperature is uniform inside the room and heat is transmitted outside the room through a glass window of area 1.2 m^2 and thickness 0.1 cm. If T^@C is the temperature outside and thermal conductivity of glass is 0.2 cal s^(-1) m^(-1) ""^@C^(-1) , then find the value of 10T - 75 close to nearest integer.