The self inductance of a coil having 100 turns is 10 mH. What is the magnetic flux linked with each turn of the coil, if a current of 4 mA is passed through the coil?

The self inductance of a coil having 400 turns is 10 mH. What is the magnetic flux through the cross section of the coil corresponding to current 2 mA ?

The self inductance of a coil having 400 turns is 10 mH. The magnetic flux through the cross section of the coil corresponding to current 2 mA is

The self inductance of a coil having 400 turns is 10 mH. The magnetic flux through the cross section of the coil corresponding to current 2 mA is

Statement I: Self-inductance of a solenoid having 1000 turns is 100 mH if the associated magnetic flux linked with each turn is 10^(-3) Wb for a current of 1 A passig through the solenoid. Statement II: The self-inductance L of a coil is defined as phi=LI when phi is the magnetic flux linked with the coil for a current I through it.

The self inductance of an inductor having 100 turns is 20 mH. Calculate the total magnetic flux linked with the coil and the magnetic flux through the cross-section of the inductor corresponding to a current of 4 mA.

The self-inductane of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 mA is found to be

The self-inductane of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 mA is found to be

The self inductance of a coil having 200 turns is 10 mH. Complete the total flux linked with the coil. Also, determine the magnetic flux through the cross section of the coil, corresponding to current of 4 mA.

The self-inductance of a coil having 200 turns is 10 milli henry. Calculate the magnetic flux through the cross-section of the coil corresponding to current of 4 milliampere. Also determine the total flux linked with each turn.