Two person `A and B` take turns in throwing a pair of dice. The first person to through 9 from both dice will win the game. If A throwns fisrt then the probability that B wins the game is.

Two person A and B take turns in throwing a pair of dice.The first person to through 9from both dice will win the game.If A throwns fisrt then the probability that B wins the game is.

Two persons A and B take turns in throwing a pair of dice. The first person to throw 9 from both dice will be awarded the prize. If A throws first, then the probability that B wins the game is 9//17 b. 8//17 c. 8//9 d. 1//9

Two persons A and B take turns in throwing a pair of dice. The first person to throw 9 from both dice will be awarded the prize. If A throws first, then the probability that B wins the game is 9//17 b. 8//17 c. 8//9 d. 1//9

Two persons A and B take turns in throwing a pair of dice. The first person to throw 9 from both will get the prize. If A throws first then the probability of B winning the prize is -

A and B alternately throw with a pair of dice. Who gets a sum of 7 points 1 th will win the game.If A starts the game,the probability of his winning is

Two persons A and B are rolling die on the condition that the person who gets 3 will win the game. If A starts the game, then find the probabilities of A and B respectively to win the game.

A and B take turns in throwing two dice, the first to throw 9 being awarded the prize. Show that their chance of winning are in the ratio 9:8.