Let us consider a copper wire having radius r and length l. Let its resistance be R. If the radius of another copper wire is `2r` and the length is `l//2` then the resistance of this, wire will be

The length and readius of a wire is l and r respectively. Its resistance is R. After hammering the radius of the wire is made (r/2) then the new resistance will be

The resistance of a wire of length l and diameter d is R . The wire is stretched to double its length. The resistance of the wire will now be

A wire of length L is drawn to a length 2L, then its resistance will.

A wire of length l has a resistance R. If half of the length is stretched to make the radius half of its original value, then the final resistance of the wire is

A wire of length l has a resistance R. If half of the length is stretched to make the radius half of its original value, then the final resistance of the wire is

A cylindrical wire of length L and radius r has a resistance R. The resistance of another wire of the same material but half its length and half its radius will be:

The mass of a copper wire of resistance R_(1) and length l_(1) is four times the mass of another copper wire of length l_(2) and resistance R_(2) . If R_(1)=R_(2) , which one of the following is correct ?