CsCl has bcc structure with `Cs^(+)` at the centre and `Cl^(-)` ion at each corner. If `r_(Cs^(+))` is `1.69Å` and `r_(Cl^(-))` is `1.81Å` what is the edge length of the cube?

CsCl crystallizes in a cubic lattice and has a Cl^(-) at each corner and Cs^(+) at the centre of unit cell. If r_(Cs^(+))=1.69 Å and r_(Cl^(-))=1.81 Å , what is the value of edge - length 'a' of the cube ? Compare this values of 'a' (calculated) from the observed density of CsCl. 3.97 gm//cm^(3). [M_((CsCl))=168.5]

In CsCl with cubic structure, Cl^(-) ions are located at each corner and Cs^(+) ions at the centre of the unit cell. If r_(Cs^(+)) and r_(Cl^(-)) and 1.69Å and 1.81Å respectively. Find the value of edge length of cube.

If the length of the body for CsCl which crystallizes into a cubic strructure with Cl^(Θ) ions at the corners and Cs^(o+) ions at the centre of the unit cell is 7 Å and the radius of he Cs^(o+) ions is 1.69Å , what is the radius of Cl^(ɵ) ions?

If the length of the body for CaCl which crystallizes into a cubic strructure with Cl^(Θ) ions at the corners and Cs^(o+) ions at the centre of the unit cell is 7 Å and the radius of he Cs^(o+) ions is 1.69Å , what is the radius of Cl^(ɵ) ions?

If ionic radii of Cs^(+) and Cl^(-) are 1.69Å and 1.81Å respectively, the edge length of unit cell is

In an ionic solid r_(c)=1.6Å and r_(a)=1.86Å . Find edge length of cubic unit cell Å

CsCl has cubic structure of ions in which Cs^(+) ion is present in the body -centre of the cube. If density is 3.99 g cm^(-3) : (a) Calculate the length of the edge of a unit cell. (b) What is the distance between Cs^(+) and Cl^(-) ions ? (c) What is the radius of Cs^(+) ion if the radius of Cl^(-) ion is 180 pm ?

If ionic radic radii of Cs^(+) and Ce^(-) are 1.69Å and 181Å respectively, the edge length of unit cell is