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(2)/(5)times(-(3)/(7)-(1)/(6)times(3)/(2...

(2)/(5)times(-(3)/(7)-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

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Using appropriate properties find.(i) -(2)/(5)xx(3)/(5)+(5)/(2)-(3)/(5)xx(1)/(6)( ii) (2)/(5)xx(-(3)/(7))^(2)-(1)/(6)xx(3)/(2)+(1)/(14)xx(2)/(5)

[((-2)/(-3))times(1)/(5)]times((-2)/(7))=((-2)/(-3))times[(1)/(5)times((-2)/(7))]

(2)/(5)x-(3)/(7)-(1)/(14)-(3)/(7)times(3)/(5)

(5)/(4)times(2)/(6)+(3)/(2)times(2)/(1)+(3)/(6)times(3)/(2)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Using appropriate properties find : (2)/(5) xx ((-3)/(7)) - (1)/(6) xx (3)/(2) + (1)/(14) xx (2)/(5) = (2)/(5) xx ((-3)/(7)) + (1)/(14) xx (2)/(5) - (1)/(cancel6) xx (cancel 3)/(2) = (2)/(5) xx ((-3)/(7) + (1)/(14) ) - (1)/(4) = (2)/(5) xx ((-6+1)/(14))- (1)/(4) = (cancel 2)/(cancel 5) xx (-cancel 5)/(cancel14) - (1)/(4) = (-1)/(7) - (1)/(4) (- 4 - 7)/(28) = (-11)/(28)

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

-(2)/(3)times(3)/(5)+(5)/(2)-(3)/(5)times(7)/(6)