The enthalpy of combustion of methane, graphite and dihydrogen at `298 K` are, `-890.3 kJ mol^(-1) -393.5 kJ mol^(-1)`, and `-285.8 kJ mol^(-1)` respectively. Enthapy of formation of `CH_(4)(g)` will be

The enthalpy of combustion of methane, graphite and dihydrogen at 298K are -890.3 kJ mol^(-1) ,- 393.5 kJ mol^(-1) and - 285.8 kJ "mol"^(-1) respectively. Enthalpy of formation of CH_(4(g)) will be ____

The enthalpy of combustion of methane, graphite and dihydrogen at 298K are -890.3 kJ*mol^(-1) , -393.5 kJ*mol^(-1) and -285.8kJ*mol^(-1) respectively. Enthalpy of formation of CH_(4)(g) will be-

The enthalpy of combustion of methane, graphite & dihydrogen at 298 K are, -890.3 kJ mol^-1, 393.5 kJ mol^-1 & 285.8 kJ mol^-1 ' respectively. Enthalpy of formation of CH_4(g) will be :

a) The enthalpy of combustion of CH_(4(g)), C_(graphite) and H_(2(g)) at 298 K are - 890.3 kJ mol^-1 , - 393.5 kJ mol^-1 and -285.8 kJ mol^-1 respectively. Calculate the enthalpy of formation of CH_(4(g)).

The enthalpy of combustion of one mole of benzene,carbon and hydrogen are-3267 kj mol-1 ,-393.5 kj mol^-1 and -285.8 kj mol^-1 respectively.Calculate the stnadard enthalpy of formation of benzene.