(18.[[2,-3,3],[2,2,3],[3,-2,2]]

it [[3, -1,18,1, -25, -2, -3]]

If matrix A= [(1, 2, 3),( 2, 3, 1),( 3, 1, 2)] then |adjA| is: (A) 18 (B) -18 (C) 324 (D) -324

Solve for x, y [(x^(2)),(y^(2))] +3 [(2x),(-3y)] = [(-5),(-18)]

2x+3y=18;x-2y=2

Simplify ((3(2)/(3))^(2)-(2 (1)/(2)))/((4(3)/(4))^(2)-(3(1)/(3))^(2))+(3(2)/(3)-2(1)/(2))/(4(3)/(4)-3(1)/(3))

Add the following -2a+5a^2-a^3+2, -5a^2 -2a^3 +4, a-a^2 +3a^3, -2a-3a^2-4, 6-3a+2a^2-2a^3

Arrange in descending order: 2^(2+3),(2^(2))^(3),2xx2^(2),(3^(5))/(3^(2)),3^(2)xx3^(@),2^(3)xx5^(2)

(18)^2-(4)^3-sqrt(1225)=(?)^2

If a,b,c,d in R^(+) such that a+b+c=18 then the maximum value of a^(2)b^(3)c^(4) is equal to 2^(18)xx3^(2)2^(18)xx3^(3)2^(19)xx3^(2)2^(18)xx3^(3)

If a ,b ,c ,d in R^+ such that a+b+c=18 , then the maximum value of a^2b^3c^4 is equal to a. 2^(18)xx3^2 b. 2^(18)xx3^3 c. 2^(19)xx3^2 d. 2^(19)xx3^3