Use elementary column operation C2 `->` C2 -2C1 in the matrix equation `[[4 ,2],[ 3, 3]]=[[1, 2 ],[0, 3]][[2 ,0],[ 1 ,1]]`

On using clementary row operation R_1 to R_1-3 R_2 in the following matrix equation [[4,2],[3,3]]=[[1,2],[0,3]][[2,0],[1,1]] we have,

Use elementary column operation C_2->C_2+2C_1 in the following matrix equation : [(2 ,1),( 2, 0)]=[(3 ,1),( 2 ,0)][(1 ,0),(-1, 1)]

Use elementary column operation C_2->C_2+2C_1 in the following matrix equation : [(2,1),(2, 0)] = [(3,1),(2,0)][(1,0),(-1, 1)]

Use elementary column operation C_(2)rarr C_(2)+2C_(1) in the following matrix equation :([2,12,0])=([3,12,0]),([1,0-1,1])

Use the elementary row operation R_(1) to R_(1)-3R_(2) in the matrix equation [{:(4,2),(3,3):}]=[{:(1,2),(0,3):}][{:(2,0),(1,1):}]

Use the elementary column operations C_(2) to C_(2)-2C_(1) in the matrix equation [{:(1,-3),(2,4):}]=[{:(1,-1),(0,1):}][{:(3,1),(2,4):}]

On using the elementary row operation R_(1) to R_(1)-3R_(2) in the matrix equation [{:(4,2),(3,3):}]=[{:(1,2),(0,3):}] [{:(2,0),(1,1):}] we get

Solve the matrix equation A[[1,2],[3,4]]=[[1,-1],[0,0],[2,3]] using concept of inverse.

On using elementary column operations C_(2)toC_(2)-2C_(1) in the following matrix equation [{:(1,-3),(2,4):}]=[{:(1,-1),(0,1):}]*[{:(3,1),(2,4):}] we have :

On using elementary operation C_(2) to C_(2) - 2C_(1) in the following matrix equation : [ (1,-3),(2,4)] = [ (1,1),(0,1)] [ (3,1),(2,4)] we have :