`CH_(3)-Ch=CH-CH=CH-CH-CH_(3),` total number of geometrical isomer is :

CH_3 - CH = CH-CH=CH-CH_3 , total number of geometrical isomer is :

Me (CH=CH-CH=C=CH-CH=CH_(2) Total number of geometrical isomers possible for above compound are:

CH_(3)-CH=C=CH-CH_(3) The possible number of geometrical isomers of this diene is_________

(i) CH_(2)=CH-CH_(2)-CH=CH_(2) (ii) CH_(2)=CH-CH=CH-CH_(3) (iii) CH_(3)-CH=CH-CH=CH-CH_(3) The numbers of possible geometrical isomers for the above compounds are

CH_(2)=CH-CH=CH-CH=CH-CH_(3) How many geometrical isomers of this compound are possible?

The number of geometrical isomers in CH_(3)CH=N-OH is

The number of geometrical isomers in CH_(3)CH=N-OH is