If `{:E(theta)=[(cos^2 theta,costhetasintheta),(costhetasintheta,sin^2theta)]:},and thetaand phi` differ by an odd multiple of `pi//2," then "E(theta)E(phi)` is a

If f(theta)=|{:(cos^2theta,costhetasintheta,-sintheta),(costhetasintheta,sin^2theta,costheta),(sintheta,-costheta," "0):}| , then find the value of f((pi)/6) .

Evalute : |{:(cos^2 theta,costhetasintheta,-sintheta),(costhetasintheta,sin^2theta,costheta),(sintheta,-costheta,0):}|

Select and write the correct answer from the given alternatives in each of the following:If AB=0 where A=[[cos^2theta,costhetasintheta],[costhetasintheta,sin^2theta]] and B=[[cos^2phi,cosphisinphi],[cosphisinphi,sin^2phi]] ,then (theta-phi) is equal to

The product of matrices A = [(cos^(2) theta, cos theta sin theta),(cos theta sin theta , sin^(2) theta)] and sin B = [(cos^(2)phi, cos phi sin phi),(cos phi sin phi, sin^(2) phi)] is a null matrix if theta - phi =

cos2thetacos2phi+sin^2(theta-phi)-sin^2(theta+phi)=

If AB=O for the matrices A=[[cos^2theta,costhetasintheta],[costhetasintheta,sin^2theta]] and B=[[cos^2phi,cosphisinphi],[cosphisinphi,sin^2phi]] then theta-phi is

If A=[(cos^2theta,costheta sintheta),(cos theta sintheta, sin^2theta)] and B=[(cos^2 phi, cos phi sin phi),(cos phisinphi,sin^2phi)], show that AB is zero matrix if theta and phi differ by an odd multiple of pi/2.