A particle undergoing simle harmonic motion has time dependent displacement given by `x(t)=Asin (pi t)/(90)`.The ratio of kinetic to potential energy of this partle at t= 210s will be :

A particle undergoes simple harmonic motion having time period T. The time taken in 3/8th oscillation is

A particle executes simple harmonic motion according to the displacement equation y = 10 cos(2 pi t + (pi)/(6))cm where t is in second The velocity of the particle at t = 1/6 second will be

A particle starts oscillating simple harmonically from its equilibrium position then, the ratio of kinetic energy and potential energy of the particle at the time T//12 is: (T="time period")

For a particle executing simple harmonic motion, the displacement x is given by x= Acosomegat . Identify the graph, which represents the variation of potential energy (U) as a function of time t and displacement x.

For a particle executing simple harmonic motion, the displacement x is given by x= Acosomegat . Identify the graph, which represents the variation of potential energy (U) as a function of time t and displacement x.

A particle starts oscillating simple harmonically from its equilibrium position then, the ration of kinetic energy and potential energy of the particle at the time T//12 is: (T="time period")

When the displacement of a particle executing simple harmonic motion is half its amplitude, the ratio of its kinetic energy to potential energy is