" ISE "25.1

2, 3.1, 5.3, 8.6, 13, 18, 25.1

A 25.0ml sample of 0.1 M HCl is titrated with 0.1 M NaOH . What is the pH of the solution at the points where 24.9 and 25.1 ml of NaOH have been added ?

Successive ionisation potentials of an element M are 8.3, 25.1, 37.9, 259.3 and 340.1ev. The formula of its bromide is

(1)/(1xx2)""^(25)C_(0)+(1)/(2xx3)""^(25)C_(1)+(1)/(3xx4)""^(25)C_(2)+…+(1)/(26xx27)""^(25)C_(25) is -

The value of (5.(25)^(n+1) + 25.(5)^(2n-1))/(25.(5)^(2n) -105(25)^(n-1)) is :

The value of ""_(25)^(-1//4 log_(5)(25)) is:

The value of 25^-(1/2) is :

Solve : (25)^(1/2)