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In LiAlH(4), metal Al is present in :...

In `LiAlH_(4)`, metal Al is present in :

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STATEMENT-1: In LiAlH_(4),Al is sp^(3) hybridised . STATEMENT-2: LiAlH_(4) is a good reducing agent . STATEMENT-3: LiAlH_(4) complex is unstable in water .

STATEMENT-1: In LiAlH_(4),Al is sp^(3) hybridised . STATEMENT-2: LiAlH_(4) is a good reducing agent . STATEMENT-3: LiAlH_(4) complex is unstable in water .

+LiAlH_(4) rarr (A), (A) is :

LiAlH_(4) is used as :

LiAlH_(4) is used as :

Carbon oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hrdride ion (H^(-)) The metal hydrogen bond in LiAlH_(4) is more than polar than metal hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reduced by NaBH_(4) The carbonyl group of amide of reduced to methylene group by LiAlH_(4)

Carbon oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hrdride ion (H^(-)) The metal hydrogen bond in LiAlH_(4) is more than polar than metal hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reduced by NaBH_(4) The carbonyl group of amide of reduced to methylene group by LiAlH_(4) Find the correct product of the following reaction:

Carbon oxygen double bond are easily reduced by NaBH_(4) or LiAlH_(4) . The actual reducing agent in these reduction is hrdride ion (H^(-)) The metal hydrogen bond in LiAlH_(4) is more than polar than metal hydrogen bond in NaBH_(4) . As a result LiAlH_(4) is strong reducing agent than NaBH_(4) . Esters, carboxylic acids, amides cannot be reduced by NaBH_(4) The carbonyl group of amide of reduced to methylene group by LiAlH_(4) , Identify X:

Assertion : LiAlH_(4) is more reactive and less selctive than NaBH_(4) as a reducing agent. Reason : LiAlH_(4) reduces both aldehydic group and double bond in conjugate position while NaBH_(4) does not.