At present Asha's age (in years) is 2 more than the square of her daughter Nisha's age. When Nisha grows to her mother's present age, Asha's age would be one year less than 10 times the present age of Nisha. Find the present ages of both Asha and Nisha.

Explanation

Let the nisha age =x year

Aasha age=2+x years

Difference of ages=`(x^2+2-x)` years

According to question

`x+(x^2+2-x)=10x-1-(1)`
`2x^2=11x+5=0`

`2x(x-5)-1(x-5)=0`

`x=5`

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