Two protons are a distance of `1 xx 10^(-10) cm` from each other. The force acting on them are

Two protons are a distance of 1 xx 10 ^(-10) cm from each other. The forces acting on them are

If the Mechanical Advantage of a lever of 100 , when a force of 10N acts as a distance of 20cm from the point of fulcrum. Calculate the force acting on the other side of the fulcrum and the distance of that force from the fulcrum.

If the Mechanical Advantage of a lever of 100 , when a force of 10N acts as a distance of 20cm from the point of fulcrum. Calculate the force acting on the other side of the fulcrum and the distance of that force from the fulcrum.

Strengths of two magnetic poles are 0.5 A m 2 A.m If they are a distance of 5 cm from each other in air, what will be the mutual force acting between them ? For what separation dose that force become 10^(-5)N ?

If two protons are moving with speed v=4.5 xx 10^(5)m//s parallel to each other then find the ratio of electrostatic and magnetic force between them : -

If two protons are moving with speed v=4.5 xx 10^(5)m//s parallel to each other then find the ratio of electrostatic and magnetic force between them : -

Two point charges , -2muC and +6muC are fixed on a table at a distance 10 cm from each other. Where should the third charge be placed so that no net force acts on it ?