`log5 + log(x+10) -1= log(21x-20)-log(2x-1)`

log5+log(5x+1)=log(x+5)+1

2log x-log(x+1)-log(x-1)=

log(x-1)+log(x-2)lt log(x+2)

Find x, if : (i) log_(10) (x + 5) = 1 (ii) log_(10) (x + 1) + log_(10) (x - 1) = log_(10) 11 + 2 log_(10) 3

Find the sum of all possible values of x satisfying simultaneous the equations log^(2)x3log x=log(x^(2))4 and log^(2)(100x)+log^(2)(10x)=14+log((1)/(x)).[ Note : Assume base of logarithm is 10.1]

2log x-log(x+1)-log(x-1) is equals to

2log x-log(x+1)-log(x-1) is equals to

Solve for x if log(x-1)+log(x+1)=log1