A block of mass m slides down an inclined plane of inclination `theta` with uniform speed The coefficient of friction between the block and the plane is `mu`. The contact force between the block and the plane is .

A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is

A block of mass m slides down an inclined plane which makes an angle theta with the horizontal. The coefficient of friction between the block and the plane is mu . The force exerted by the block on the plane is

A block of mass 2 kg slides down an incline plane of inclination 30°. The coefficient of friction between block and plane is 0.5. The contact force between block and plank is :

A block of mass 2 kg slides down an incline plane of inclination 30°. The coefficient of friction between block and plane is 0.5. The contact force between block and plank is :

A block of mas m begins to slide down on an inclined plane of inclination theta . The force of friction will be

A block is stationary on an inclined plane If the coefficient of friction between the block and the plane is mu then .

A block of mass m slides down a rough inclined plane of inclination theta with horizontal with zero initial velocity. The coefficient of friction between the block and the plane is mu with theta gt tan^(-1)(mu) . Rate of work done by the force of friction at time t is