A particle is moving with speed `6 m//s` along the direction of `vec(A) =2 hat i+2 hat j- hat k`, then its velocity is :

A particle is moving with speed 6m//s along the direction of vec(A)=2hat(i)+2hat(j)-hat(k) , then its velocity is :

A particle is moving with speed 6m//s along the direction of vec(A)=2hat(i)+2hat(j)-hat(k) , then its velocity is :

A particle is moving with speed 6m/s along the direction of 2hat(i)+2hat(j)-hat(k) find the velocity vector of a particle ?

A particle is moving with a constant acceleration vec(a) = hat(i) - 2 hat(j) m//s^(2) and instantaneous velocity vec(v) = hat(i) + 2 hat(j) + 2 hat(k) m//s then rate of change of speed of particle 1 second after this instant will be :

A particle is moving with a constant acceleration vec(a) = hat(i) - 2 hat(j) m//s^(2) and instantaneous velocity vec(v) = hat(i) + 2 hat(j) + 2 hat(k) m//s then rate of change of speed of particle 1 second after this instant will be :

Direction - cosines of vec(a)=hat(i)+hat(j)-2hat(k) are :

Statement 1: A component of vector vec b=4 hat i+2 hat j+3 hat k in the direction perpendicular to the direction of vector vec a= hat i+ hat j+ hat ki s hat i- hat jdot Statement 2: A component of vector in the direction of vec a= hat i+ hat j+ hat k is 2 hat i+2 hat j+2 hat kdot

Statement 1: A component of vector vec b=4 hat i+2 hat j+3 hat k in the direction perpendicular to the direction of vector vec a= hat i+ hat j+ hat ki s hat i- hat jdot Statement 2: A component of vector in the direction of vec a= hat i+ hat j+ hat k is 2 hat i+2 hat j+2 hat kdot

Statement 1: A component of vector vec b=4 hat i+2 hat j+3 hat k in the direction perpendicular to the direction of vector vec a= hat i+ hat j+ hat ki s hat i- hat jdot Statement 2: A component of vector in the direction of vec a= hat i+ hat j+ hat k is 2 hat i+2 hat j+2 hat kdot

Find the work done in moving a particle along a vector vec S= (4 hat i - hat j + 7 hat k) if the applied force is vec F = (vec i +2 vec j -vec k) newton. vec S is in metre.