A particle of mass `m` describes a circle of radius `r` . The centripetal acceleration of the particle is `(4)/(r^(2))` . What will be the momentum of the particle ?

A particle of mass m describes a circle of radius r with a uniform speed v. The centripetal acceleration of the pariticle is 4 / r^(2) .What is the magnitude of the linear momentum of the particle ?

A particle of mass m is moving on a circular path of radius r . Centripetal acceleration of the particle or radius r . Centripetal acceleration of the particle depends on time t according to relation a_(c ) = kt^(2) . What power is delievered to the particle ?

A particle is moving at uniform speed 2 ms^(-1) along a circle of radius 0.5m .The centripetal acceleration of particle is

If KE of the particle of mass m performing UCM in a circle of radius r is E. Find the acceleration of the particle

If KE of the particle of mass m performing UCM in a circle of radius r is E. Find the acceleration of the particle

A particle of mass m is moving in a circle of radius r. The centripetal acceleration (a_(c)) of the particle varies with the time according to the relation, a_(c)=Kt^(2) , where K is a positive constant and t is the time. The magnitude of the time rate of change of angular momentum of the particle about the centre of the circle is

A particle with the constant speed in a circle of radius r and time period T.The centripetal acceleration of a particle is