(x+y-8)/(2)=(x+2y-14)/(3)=(3x+y-12)/(11)

Solve the following equations by Cramer’s method. (x + y - 8)/(2) = (x + 2y - 14)/(3) = (3x - y)/(4)

Find x and y if :- ((x+2y, 14),(-3, y-2))=((4, 14),(-3, 7+3x)) .

Solve by cross-multiplication method. (i) 8x-3y=12,5x=2y +7 (ii) 6x+ 7y -11 =0, 5x+ 2y =13 (iii) (2)/(x)+(3)/(y) =5, (3)/(x) -(1)/(y) +9=0

{:(2x - 3y = - 13),(3x - 2y = - 12):}

Factorise (2x+3y)^(2)+14(2x+3y)(3x-y)-32(3x-y)^(2) .

Factorise (2x+3y)^(2)+14(2x+3y)(3x-y)-32(3x-y)^(2) .

If x=5 and y=-2 , then find the value of (i) (8x-2y+5)/(2x+4ty+12) " "(ii) (5x-6y-7)/(3x+6y+12)

Solve by the method of elimination 2x-y=3,3x +y=7 (ii) x-y=5, 3x+ 2y = 25 (iii) (x)/(10 ) +(y)/(5) =14 ,(x)/( 8) + (y)/( 6) =15 (iv) 3(2x+y) =7xy,3 (x+3y ) =11xy (v) (4)/(x) +5y =7,(3)/(x) +4y =5 (vi) 13x +11y = 70,11x +13y =74