10*(-2-(1)/(3)i)^(3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

((1-i)^(3))/(1-i^(3))=-2

If sum_(i=1)^(10) ( (""^10C_(i-1))/(""^10C_i + ""^10C_(i-1) ))^3 = (k)/(11) , then k equals :

Add(i)(7)/(10)+(2)/(15) (ii) 2((2)/(3))+3((1)/(2))

Let z_1=((1+sqrt(3)i)^2(sqrt(3)-i))/(1-i) and z_2=((sqrt(3)+i)^2(1-sqrt(3)i))/(1+i) then

If z=(-1)/(2)+i(sqrt(3))/(2) , then 8+10z+7z^(2) is equal to a) -(1)/(2)-i(sqrt(3))/(2) b) (1)/(2)+isqrt(3)/(2) c) -(1)/(2)+i(3sqrt(3))/(2) d) (sqrt(3))/(2)i

The value of ((1+sqrt(3)i)/(1 - sqrt(3)i))^(10) is