" d) "i^(38)

Simplify : i^(38)

Evaluate : (i) (2^(38) + 2^(37) + 2^(36))/(2^(39) + 2^(38) + 2^(37)) (ii) [(64^((1)/(2)))^((1)/(6))]^(2)

a) 24 b) 80 c) 38 d) 32

(a) 543.24 (b) 49 (c) 16 (d) 37 (a) 38 (c)

The HCF of 95 and 152 , is (a) 57 (b) 1 (c) 19 (d) 38

The HCF of 95 and 152 , is (a) 57 (b) 1 (c) 19 (d) 38

In Fig.72, if A B || C D and A E || B D , then the value of x is (a) 38 (b) 48 (b) 58 (d) 68

sin^(2)22^(@)+sin^(2)38^(@)+sin22^(@) sin38^(@)=

Show that : (i) t a n" "48o" "t a n" "23o" "t a n" "42o" "t a n" "67o" "=" "1(i i) cos" "38o" "cos" "52o" "" "s in" "38o" "s in" "52o" "=" "0

S={1,2,3,....20} if 3 numbers are chosen at random from S, the probability for they are in A.P.is (A) (3)/(38) (B) (35)/(33) (C) (33)/(35) (D) (1)/(38)