A particle performing SHM starts equilibrium position and its time period is 16 seconds. After 2 seconds its velocity is `pi m//s`. Amplitude of oscillation is
`(cos 45^(@) = 1/(sqrt(2)))`

A particle performing S.H.M. about equilibrium position. Then the velocity of the particle is

A particle performing SHM is found at its equilibrium position at t = 1s and it is found to have a speed 0.25 = m//s at t=2s. If the period of oscillation is 6. Calculate amplitude of oscillation.

A particle performing SHM is found at its equilibrium position at t = 1s and it is found to have a speed 0.25 m//s at t=2s. If the period of oscillation is 6. Calculate amplitude of oscillation.

A particle performing SHM is found at its equilibrium position at t = 1s and it is found to have a speed 0.25 = m//s at t=2s. If the period of oscillation is 6. Calculate amplitude of oscillation.

The time taken by a particle performing SHM on a straight line to pass from point A to B where its velocities are same is 2 seconds .After another 2 seconds it return to B The time period of oscillation is (in seconds)

The time taken by a particle performing SHM on a straight line to pass from point A to B where its velocities are same is 2 seconds . After another 2 second it returns to B .The time peroid of oscillation is (in seconds):

This time period of a particle undergoing SHM is 16 s. It starts motion from the mean position. After 2 s, its velocity is 0.4 ms^(-1) . The amplitude is

A body performing SHM about its mean position with period 24 s, after 4 s its velocity is pi m//s , then its path will be