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At infinite dilution, when the dissociat...

At infinite dilution, when the dissociation of electrolyte is complete, each ion makes a definite contribution towards the molar conductance of electrolyte, irrespective of the nature of the other ion with which it is associated.
the molar conductance of an electrolyte at infinite dilution can be expressed as the sum of the contributions from its individual ions.
`A_(x)B_(y) rarr xA^(y+)+yB^(x-)`
`Lambda_(m)^(@)(A_(x)B_(y))=xlambda_(A^(y+))^(@)+ylambda_(B^(x-))^(@)`
where, x and y are the number of cations and anions respectively.
The degree of ionisation `'alpha'` of weak electrolyte can be calculated as :
`alpha=Lambda_(m)/Lambda_(m)^(@)`
The molar conductances at infinite dilution for electrolytes BA and CA are 140 and 120 `ohm^(-1) cm^(2) mol^(-1)`. If the molar conductance at infinite dilute dilution of BX is 198 `ohm^(-1) cm^(2) mol^(-1)`, then at infinite dilution, the molar conductance of CX is :

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At infinite dilution, when the dissociation of electrolyte is complete, each ion makes a definite contribution towards the molar conductance of electrolyte, irrespective of the nature of the other ion with which it is associated. the molar conductance of an electrolyte at infinite dilution can be expressed as the sum of the contributions from its individual ions. A_(x)B_(y) rarr xA^(y+)+yB^(x-) Lambda_(m)^(@)(A_(x)B_(y))=xlambda_(A^(y+))^(@)+ylambda_(B^(x-))^(@) where, x and y are the number of cations and anions respectively. The degree of ionisation 'alpha' of weak electrolyte can be calculated as : alpha=Lambda_(m)/Lambda_(m)^(@) The unit of molar conductance of an electrolyte solution will be :

The molar conductance at infinite dilution for electrolytes BA and CA are 140 and 120 ohm^(-1) Cm^(2) mol^(-1) respectively. If the molar conductance at infinite dilution of BX is 198 ohm^(-1) cm^(2) mol(-1), then then at infinite dilution, the molar conductance of is:

The molar conductance at infinite dilution for electrolytes BA and CA are 140 and 120 ohm^(-1) Cm^(2) mol^(-1) respectively. If the molar conductance at infinite dilution of BX is 198 ohm^(-1) cm^(2) mol^(-1) , then then at infinite dilution, the molar conductance of is:

At infinite dilution, when the dissociation of electrolyte is complete, each ion makes a definite contribution towards the molar conductance of electrolyte, irrespective of the nature of the other ion with which it is associated. the molar conductance of an electrolyte at infinite dilution can be expressed as the sum of the contributions from its individual ions. A_(x)B_(y) rarr xA^(y+)+yB^(x-) Lambda_(m)^(@)(A_(x)B_(y))=xlambda_(A^(y+))^(@)+ylambda_(B^(x-))^(@) where, x and y are the number of cations and anions respectively. The degree of ionisation 'alpha' of weak electrolyte can be calculated as : alpha=Lambda_(m)/Lambda_(m)^(@) Which of the following solution will have highest value of the molar conductance of CH_(3)COOH ?

At infinite dilution, when the dissociation of electrolyte is complete, each ion makes a definite contribution towards the molar conductance of electrolyte, irrespective of the nature of the other ion with which it is associated. the molar conductance of an electrolyte at infinite dilution can be expressed as the sum of the contributions from its individual ions. A_(x)B_(y) rarr xA^(y+)+yB^(x-) Lambda_(m)^(@)(A_(x)B_(y))=xlambda_(A^(y+))^(@)+ylambda_(B^(x-))^(@) where, x and y are the number of cations and anions respectively. The degree of ionisation 'alpha' of weak electrolyte can be calculated as : alpha=Lambda_(m)/Lambda_(m)^(@) The ionic conductances of Al^(3+) and SO_(4)^(2-) ions at infinite dilution are x and y ohm^(-1) cm^(2) mol^(-1) respectively. If Kohlrausch's law is valid then molar conductance of aluminium sulphate at infinite dilution will be :

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