An alternating voltage `V = V_(0) sin omegat` is applied across a circuit. As a result, a current `I = I_(0) sin (omegat – p/2)` flows in it. The power consumed per cycle is

An alternating potential V = underset(o)(V) sin omega t is applied across a circuit. As a result the current, I = underset(o)(I)sin(omegat - pi/2) flows in it. The power consecutive in the circuit per cycle is

A small signal voltage V(t)=V_(0)sin omegat is applied across an ideal capacitor C :

A small signal voltage V(t)=V_(0)sin omegat is applied across an ideal capacitor C :

A small signal voltage V(t)=V_0 sin omegat is applied across an ideal capacitor C:

Show that an alternating voltage V=V_m sin omegat applied to a resistor R drives a current i= i sin omega t in the resistor.