[(x+1)/(2)+(y-1)/(3)=8],[(x-1)/(3)+(y+1)/(2)=9]

Solve for x and y : (x+1)/(2)+(y-1)/(3)=9, (x-1)/(3)+(y+1)/(2)=8 .

(x+1)/(2)+(y-1)/(3)=9,(x-1)/(3)+(y+1)/(2)=8 In the above problem y= ……….

Solve the following equations: (x+1)/(2)+(y-1)/(3)=8" and "(x-1)/(3)+(y+1)/(2)=9

(x+1)/(2)+(y+1)/(3)=9,(x-1)/(3)+(y+1)/(2)=8 then x=………

Solve by the elimination method: (x+1)/(2)+(y-1)/(3)=9 and (x+1)/(3)+(y-1)/(2)=8

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

Solve the following system of equations: (1)/(3x+y)+(1)/(3x-y)=(3)/(4),quad (1)/(2(3x+y))-(1)/(2(3x-y))=-(1)/(8)

(4)/(x)+(3)/(y)=1,(8)/(x)-(9)/(y)=7